First of all, I know the proof for a Poincaré type inequality for a closed subspace of H1 H 1 which does not contain the non zero constant functions. Suppose not, then there are ck → ∞ c k → ∞ such that 0 ≠uk ∈ H1(U) 0 ≠ u k ∈ H 1 ( U) with.The main contribution is the conditional Poincar{\'e} inequality (PI), which is shown to yield filter stability. The proof is based upon a recently discovered duality which is used to transform the nonlinear filtering problem into a stochastic optimal control problem for a backward stochastic differential equation (BSDE). Based on these dual ...Degenerate Poincaré-Sobolev inequalities. We study weighted Poincaré and Poincaré-Sobolev type inequalities with an explicit analysis on the dependence on the A_p constants of the involved weights. We obtain inequalities of the form \left (\frac {1} {w (Q)}\int_Q|f-f_Q|^ {q}w\right )^\frac {1} {q}\le C_w\ell (Q)\left (\frac {1} {w (Q)}\int_Q ...We then establish a comparison procedure with the well studied random transposition model in order to obtain the corresponding functional inequalities. While our method falls into a rich class of comparison techniques for Markov chains on different state spaces, the crucial feature of the method - dealing with chains with a large distortion ...ABSTRACT. We show that a large class of domains D in RI including John domains satisfies the improved Poincare inequality. IIU(x) - UD1ILq(D) < clIVu(x)d(x, 19D)31ILP(D) where …Using the aforementioned Poincaré-type inequality on the boundary of the evolving hypersurface, we obtain a novel Brunn--Minkowski inequality in the weighted-Riemannian setting, amounting to a certain concavity property for the weighted-volume of the evolving enclosed domain. All of these results appear to be new even in the classical non ...Jan 1, 2021 · In different from Sobolev’s inequality, the geometry of domain is essential for Poincare inequality. Quite a number of results on weighted Poincare inequality are available e.g. in [9, 17, 27, 36]. We cite [8, 17, 33] for further continuation of those results. For a weighted capacity characterization of this inequalities see, . Racial, gender, age and socio-economic inequalities lead to discrimination against some people everyday. These inequalities are present in such aspects as education, the workplace, politics, community and even health care.Lecture Five: The Cacciopolli Inequality The Cacciopolli Inequality The Cacciopolli (or Reverse Poincare) Inequality bounds similar terms to the Poincare inequalities studied last time, but the other way around. The statement is this. Theorem 1.1 Let u : B 2r → R satisfy u u ≥ 0. Then | u| ≤2 4 2 r B 2r \Br u . (1) 2 Br First prove a Lemma.The Poincar ́ e inequality is an open ended condition By Stephen Keith and Xiao Zhong* Abstract Let p > 1 and let (X, d, μ) be a complete metric measure space with μ Borel and doubling that admits a (1, p)-Poincar ́ e inequality. Then there exists ε > 0 such that (X, d, μ) admits a (1, q)-Poincar ́ e inequality for every q > p−ε, quantitatively.Below is the proof of Poincaré's inequality for open, convex sets. It is taken from "An Introduction to the Regularity Theory for Elliptic Systems, Harmonic Maps and Minimal Graphs" by Giaquinta and Martinazzi.Poincare type inequality is one of the main theorems that we expect to be satisfied (and meaningful) for abstract spaces. The Poincare inequality means, roughly speaking, that the ZAnorm of a function can be controlled by the ZAnorm of its derivative (up to a universal constant). It is well-known that the Poincare inequality implies the Sobolev Weighted Poincaré inequalities for Hörmander vector fields and local regularity for a class of degenerate elliptic equations. B. Franchi G. Lu R. Wheeden. Mathematics. 1995. In this note we state weighted Poincaré inequalities associated with a family of vector fields satisfying Hörmander rank condition.Poincaré Inequality Stephen Keith ABSTRACT. The main result of this paper is an improvement for the differentiable structure presented in Cheeger [2, Theorem 4.38] under the same assumptions of [2] that the given metric measure space admits a Poincaré inequality with a doubling mea sure. To be precise, it is shown in this paper that the ...In this paper, we prove a sharp anisotropic Lp Minkowski inequality involving the total Lp anisotropic mean curvature and the anisotropic p-capacity for any bounded domains with smooth boundary in ℝn. As consequences, we obtain an anisotropic Willmore inequality, a sharp anisotropic Minkowski inequality for outward F-minimising sets and …Almost/su ciently good connectivity equivalent to Poincar e inequalities Corollaries and other forms of Poincar e inequalities Self-improvement 1 Applies also to other inequalities which are related to Poincar e inequalities. 2 Pointwise Hardy inequalities (j.w. Antti V ah akangas, to be submitted soon). 3 \Direct" approach, curve based.inequalities as (w,v)-improved fractional inequalities. Our ﬁrst goal is to obtain such inequalities with weights of the form wF φ (x) = φ(dF (x)), where φ is a positive increasing function satisfying a certain growth con-dition and F is a compact set in ∂Ω. The parameter F in the notation will be omitted whenever F = ∂Ω. This paper is devoted to the study of fractional (q, p)-Sobolev-Poincaré in- equalities in irregular domains. In particular, the author establishes (essentially) sharp fractional (q, p)-Sobolev-Poincaré inequalities in s-John domains and in domains satisfying the quasihyperbolic boundary conditions. When the order of the fractional derivative tends to 1, our results tend to the results for ...14 Jan 2020 ... ∇f 2dµ, proof by expansion in Hermite polynomials. Loucas Pillaud-Vivien. Poincaré Constant estimation. Page 11. Poincaré Inequality.Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers.. Visit Stack ExchangeAfter that, Lam generalized results of Li and Wang to manifolds satisfying a weighted Poincaré inequality by assuming that the weight function is of sub-quadratic growth of the distance function. By using a weighted Poincaré inequality, Lin [ 17 ] established some vanishing theorems under various pointwise or integral curvature conditions.Jules Henri Poincaré (UK: / ˈ p w æ̃ k ɑːr eɪ /, US: / ˌ p w æ̃ k ɑː ˈ r eɪ /; French: [ɑ̃ʁi pwɛ̃kaʁe] ⓘ; 29 April 1854 - 17 July 1912) was a French mathematician, theoretical physicist, engineer, and philosopher of science.He is often described as a polymath, and in mathematics as "The Last Universalist", since he excelled in all fields of the discipline as it existed ...Cheeger, Hajlasz, and Koskela showed the importance of local Poincaré inequalities in geometry and analysis on metric spaces with doubling measures in [9, 15].In this paper, we establish a family of global Poincaré inequalities on geodesic spaces equipped with Borel measures, which satisfy a local Poincaré inequality along with certain other geometric conditions.tain the exact constants in the inequalities. Finally, we apply our result to study solutions of ordinary differential equations with given average value. 1. Introduction. If 1 < q, p < <x>, and -oo < a < b < oo, there is a constant TPA depending on a, b such that the one dimensional Poincaré type inequality / (b i rb i \l/ci / rb \1'ppoincare inequality with spectral gap 1 where 1 is the rst nonzero eigenaluev of the laplace beltrami operator with domain L= C 1(M) (in the setting with boundary take C1 0 or H 0) then we can show through fourier means or ariationalv means that Var(f) 1 1 E(f;f):If this is not the inequality that you want, I'd suggest making another question in order to avoid confusing edits. $\endgroup$ - Jose27 Sep 25, 2021 at 9:10The symmetric exponential measure on ℝ, i.e., the measure with density 1 2 e − | t |, satisfies Poincaré inequality with constant 4. Consequently, the same is true for the measure on ℝ n which is the n-fold product of this measure. The canonical Gaussian measure on ℝ and thus on ℝ n satisfies logarithmic Sobolev inequality with ... In 1999, Bobkov [ 10] has shown that any log-concave probability measure satisfies the Poincaré inequality. Here log-concave means that ν ( dx ) = e −V (x)dx where V is a convex function with values in \ (\mathbb R \cup \ {+ \infty \}\). In particular uniform measures on convex bodies are log-concave.This paper deduces exponential matrix concentration from a Poincaré inequality via a short, conceptual argument. Among other examples, this theory applies to matrix-valued functions of a uniformly log-concave random vector. The proof relies on the subadditivity of Poincaré inequalities and a chain rule inequality for the trace of the matrixAbstract. In order to describe L2-convergence rates slower than exponential, the weak Poincaré inequality is introduced. It is shown that the convergence rate of a Markov semigroup and the ...Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company, and our products.Poincar´e inequalities play a central role in the study of regularity for elliptic equa-tions. For speciﬁc degenerate elliptic equations, an important problem is to show the existence of such an inequality; however, an extensive theory has been developed by assuming their existence. See, for example, [17, 18]. In [5], the ﬁrst and third Abstract. In an \(n\)-dimensional bounded domain \(\Omega_n\), \(n\ge 2\), we prove the Steklov-Poincaré inequality with the best constant in the case where \(\Omega_n\) is an \(n\)-dimensional ball.We also consider the case of an unbounded domain with finite measure, in which the Steklov-Poincaré inequality is proved on the basis of a Sobolev inequality.We prove a Poincaré inequality for Orlicz–Sobolev functions with zero boundary values in bounded open subsets of a metric measure space. This result generalizes the (p, p)-Poincaré inequality for Newtonian functions with zero boundary values in metric measure spaces, as well as a Poincaré inequality for Orlicz–Sobolev …Poincare inequality, Poincare domains, John domains, domains satisfy- ing a quasihyperbolic boundary condition. This paper was written while the author was ...Poincare type inequality is one of the main theorems that we expect to be satisfied (and meaningful) for abstract spaces. The Poincare inequality means, roughly speaking, that the ZAnorm of a function can be controlled by the ZAnorm of its derivative (up to a universal constant). It is well-known that the Poincare inequality implies the Sobolev $\begingroup$ @Jeff: Thank you for your comment. What's in my mind is actually the mixed Dirichlet-Neumann boundary problem: an elliptic equation with zero on one portion of the boundary and zero normal derivative on the rest of the portion.The weighted Poincaré inequalities in weighted Sobolev spaces are discussed, and the necessary and sufficient conditions for them to hold are given. That is, the Poincaré inequalities hold if, and only if, the ball measure of non-compactness of the natural embedding of weighted Sobolev spaces is less than 1. ... The weighted Poincare ...Tour Start here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this siteexamples which show that this inequality is false for all p < 1, even if q is very small, Ω is a ball, and u is smooth (one such example is given near the end of Section 1). Nevertheless, we shall show that, under a rather mild condition on ∇u, one can prove such an inequality in any John domain for all 0 < p < 1 (see Theorem 1.5).The inequality (3.3) follows from (3.12) and (3.13) and the theorem is proved. a50 We call inequality (3.3) a "weighted Poincaré-type inequality for stable processes." It is interesting to note that the eigenfunction ϕ 1 in (3.3) can be replaced by various other simi- larly generated functions from P x {τ D >t}. For example, we may ...We also note that the Poincare´ and Sobolev inequalities contained in [9] show gains onthe leftofthe form1 ≤ q≤ (n/(n−1))p+δforsomeδ>0. However, ourPoincare´ inequalities have gainsonboththe leftand the right, anditisforthis reason (among those mentioned) that we do not obtain the same sharp exponents that are contained in [9].Scott Winship is one of the most prominent academic skeptics of the idea that rising inequality is harming the American economy. Scott Winship started his career as a moderate Democrat, believing in progressive solutions to the US’s economi...$\begingroup$ In general, computing the exact value of the Poincare-Friedrichs constant is quite challenging and is only known for some domains. I can't quite seem to find any relevant articles on the Google right now, but I'll report back if I do find something $\endgroup$Indeed, such estimates are directly related to well-known inequalities from pure mathematics (e.g logarithmic Sobolev and Poincáre inequalities). In probability theory, Brascamp-Lieb and Poincaré inequalities are two very important concentration inequalities, which give upper bounds on variance of function of random variables.Poincar´e inequalities play a central role in the study of regularity for elliptic equa-tions. For speciﬁc degenerate elliptic equations, an important problem is to show the existence of such an inequality; however, an extensive theory has been developed by assuming their existence. See, for example, [17, 18]. In [5], the ﬁrst and thirdThe first part of the Sobolev embedding theorem states that if k > ℓ, p < n and 1 ≤ p < q < ∞ are two real numbers such that. and the embedding is continuous. In the special case of k = 1 and ℓ = 0, Sobolev embedding gives. This special case of the Sobolev embedding is a direct consequence of the Gagliardo–Nirenberg–Sobolev inequality.We also discuss exponential integrability under Poincaré inequalities and its consequence to sharp diameter upper bounds on spectral gaps. AB - We present a simple proof based on modified logarithmic Sobolev inequalities, of Talagrand's concentration inequality for the exponential distribution. We actually observe that every measure satisfying ...Henri Poincaré was a mathematician, theoretical physicist and a philosopher of science famous for discoveries in several fields and referred to as the last polymath, one who could make significant contributions in multiple areas of mathematics and the physical sciences. This survey will focus on Poincaré's philosophy.Hence the best constant of Poincare inequality is just $1/\lambda_1$? Am I correct? I think this problem has been well studied. So if you know where I can find a good reference, please kindly direct me there. Thank you! sobolev-spaces; calculus-of-variations; Share. Cite. FollowLecture Five: The Cacciopolli Inequality The Cacciopolli Inequality The Cacciopolli (or Reverse Poincare) Inequality bounds similar terms to the Poincare inequalities studied last time, but the other way around. The statement is this. Theorem 1.1 Let u : B 2r → R satisfy u u ≥ 0. Then | u| ≤2 4 2 r B 2r \Br u . (1) 2 Br First prove a Lemma. Title: An optimal Poincaré-Wirtinger inequality in Gauss space. Authors: Barbara Brandolini, Francesco Chiacchio, Antoine Henrot, Cristina Trombetti. Download PDF Abstract: Let $\Omega$ be a smooth, convex, unbounded domain of $\R^N$. Denote by $\mu_1(\Omega)$ the first nontrivial Neumann eigenvalue of the Hermite operator in $\Omega$; we ...mod03lec07 The Gaussian-Poincare inequality. NPTEL - Indian Institute of Science, Bengaluru. 180 08 : 52. Poincaré Conjecture - Numberphile. Numberphile. 2 30 : 29. Lecture 15 (Part 2): Proof of Poincare inequality, Existence and Uniqueness for Possion problem. Sukkur IBA University- Mathematics. 1 ...www.imstat.org/aihp Annales de l'Institut Henri Poincaré - Probabilités et Statistiques 2013, Vol. 49, No. 1, 95-118 DOI: 10.1214/11-AIHP447 © Association des ...This algebraic property is at the core of all Korn-type inequalities, it means that derivatives of \(D^au\) are in the span of the derivatives of \(D^s u\).Note that the Schwarz Theorem also implies \(D^a\,\nabla =0\) which is central in the construction of the De Rham complex. \(\textcircled {3}\) The rigidity constants, as defined in (), () and (), measure the defects of axisymmetry of the ...We show that unbounded John domains (and even a larger class of domains than John domains) satisfy the weighted Poincar(cid:19)e inequality inf a 2 R k u ( x ) − a k L q ( D,w 1 ) (cid:20) C kr u (…The main aim of this note is to prove a sharp Poincaré-type inequality for vector-valued functions on $\mathbb{S}^2$ that naturally emerges in the context of micromagnetics of spherical thin films. On a Sharp Poincaré-Type Inequality on the 2-Sphere and its Application in Micromagnetics | SIAM Journal on Mathematical AnalysisTHE UNIFORM KORN - POINCARE INEQUALITY´ IN THIN DOMAINS L’INEGALIT´ E DE KORN - POINCAR´ E´ DANS LES DOMAINES MINCES MARTA LEWICKA AND STEFAN MULLER¨ Contents 1. Introduction 2 2. The main theorems 4 3. Remarks and an outline of proofs 6 4. An example where the constant Ch blows up 8 5. An approximation of ∇u 10 …See also: Poincaré Inequality. Share. Cite. Follow edited Apr 13, 2017 at 12:21. Community Bot. 1. answered Jul 11, 2014 at 20:23. user147263 user147263 $\endgroup$ ... Poincare Inequality on compact Riemannian manifold. 0. Integration by parts on compact, non-orientable Riemannian manifold with boundary.In mathematics, inequalities are a set of five symbols used to demonstrate instances where one value is not the same as another value. The five symbols are described as “not equal to,” “greater than,” “greater than or equal to,” “less than”...Poincaré Inequality Add to Mendeley Elliptic Boundary Value Problems of Second Order in Piecewise Smooth Domains Mikhail Borsuk, Vladimir Kondratiev, in North-Holland Mathematical Library, 2006 2.2 The Poincaré inequality Theorem 2.9 The Poincaré inequality for the domain in ℝ N (see e.g. (7.45) [129] ).Hardy's inequality is proved with the same choice of ψ that gave Hilbert's inequality. One interesting consequence should be mentioned. Suppose f(z) = Σa n z n is analytic in |z| < 1. If Σ|a n | < ∞, then f has a continuous extension to |z| ≤ 1, but the converse is false (see Exercise 7).Hardy's inequality shows, however, that if f′ ∈ H 1 (or equivalently, in light of Theorem 3.11 ...Chapter. Sobolev inequality, Poincaré inequality and parabolic mean value inequality. Peter Li. Geometric Analysis. Published online: 5 June 2012. Article. Sharp Caffarelli-Kohn-Nirenberg inequalities on Riemannian manifolds: the influence of curvature. Van Hoang Nguyen.The main contribution is the conditional Poincaré inequality (PI), which is shown to yield filter stability. The proof is based upon a recently discovered duality which is used to transform the nonlinear filtering problem into a stochastic optimal control problem for a backward stochastic differential equation (BSDE).Matteo Levi, Federico Santagati, Anita Tabacco, Maria Vallarino. We prove local Lp -Poincaré inequalities, p ∈ [1, ∞], on quasiconvex sets in infinite graphs endowed with a family of locally doubling measures, and global Lp -Poincaré inequalities on connected sets for flow measures on trees. We also discuss the optimality of our results.The inequality provides the sharp upper bound on convex domains, in terms of the diameter alone, of the best constants in Poincaré inequality. The key point is the implementation of a refinement of the classical Pólya-Szegö inequality for the symmetric decreasing rearrangement which yields an optimal weighted Wirtinger inequality.Sobolev 空间: 庞加莱不等式 (Poincaré inequalities) - Sobolev 空间中的 Poincaré 不等式往往在微分方程弱解存在性的证明中扮演一个基础且关键的作用; 如典型的二阶椭圆方程. 我们将给出两种主要的 Poincaré 不等式并给出证明.Regarding this point, a parabolic Poincaré type inequality for u in the framework of Orlicz space, which is a larger class than the L p space, was derived in [12]. In this paper we obtain Sobolev-Poincaré type inequalities for u with weight w = w ( x, t) in the parabolic A p class and G ∈ L w p ( Ω × I, R n) for some p > 1, in Theorem 3 ...In this paper we study global Poincare inequalities on balls in a large class of sub-Riemannian manifolds satisfying the generalized curvature dimension inequality introduced by F.Baudoin and N ...The strong Orlicz-Poincaré inequality coincides with the ones considered by Heikkinen and Tuominen in, for example, [Hei10,HT10,Tuo04,Tuo07]. The inequalities of Feng-Yu Wang [Wan08] are of a ...We observe some higher order Poincare-type inequalities on a closed manifold, which is inspired by Hurwitz's proof of the Wirtinger's inequality using Fourier theory. We then give some geometric implication of these inequalities by applying them on the sphere. More specifically, by applying them to the support function of a convex hypersurface in the Euclidean space, we obtain some sharp ...The Poincaré, or spectral gap, inequality is the simplest inequality which quantifies ergodicity and controls convergence to equilibrium of the semigroup P = ( P t ) t≥0 …The Poincaré inequality need not hold in this case. The region where the function is near zero might be too small to force the integral of the gradient to be large enough to control the integral of the function. For an explicit counterexample, let. Ω = {(x, y) ∈ R2: 0 < x < 1, 0 < y < x2} Ω = { ( x, y) ∈ R 2: 0 < x < 1, 0 < y < x 2 }In very many nonlinear problems, though not absolutely all, such modified version of the Gagliardo-Nirenberg inequality for domains proves equally effective as its original version for the whole space. When Ω = Rn then H1 0(Ω) ≡ H1(Ω), so the Ladyzhenskaya's inequality is true for all functions u ∈ H1 0.Edit: The below answer is really nice. But here let me point out a more generally Poincare inequality which I learned recently. Actually the Poincare inequality hold for any E ⊂ Ω E ⊂ Ω such that |E| > 0 | E | > 0, then. ∫Ω|u −uE|2dx ≤ C∫Ω|∇u|2dx ∫ Ω | u − u E | 2 d x ≤ C ∫ Ω | ∇ u | 2 d x. Hence we could take E E ...mod03lec07 The Gaussian-Poincare inequality. NPTEL - Indian Institute of Science, Bengaluru. 180 08 : 52. Poincaré Conjecture - Numberphile. Numberphile. 2 30 : 29. Lecture 15 (Part 2): Proof of …For Ahlfors Q-regular spaces, we obtain a characterization of p-Poincare inequality for p > Q in terms of the p-modulus of quasiconvex curves connecting pairs of points in the space. A related ...Therefore, fractional Poincare inequality hold for all s ∈ (0, 1). Example 2 D as in Theorem 1.2. For s ∈ (1 2, 1) there is an easy geometric characterization for any domain Ω to satisfy LS (s) condition. A domain Ω satisfies LS(s) condition if and only if sup x 0 ∈ R n, ω ∈ σ B C (L Ω (x 0, ω)) < ∞, where the sets L Ω (x 0, ω ...Hardy's inequality is proved with the same choice of ψ that gave Hilbert's inequality. One interesting consequence should be mentioned. Suppose f(z) = Σa n z n is analytic in |z| < 1. If Σ|a n | < ∞, then f has a continuous extension to |z| ≤ 1, but the converse is false (see Exercise 7).Hardy's inequality shows, however, that if f′ ∈ H 1 (or equivalently, in light of Theorem 3.11 ...So basically, I have proved the Poincare's inequality for p = 1 case. That is, for u ∈ W 1, 1 ( Ω), I have | | u − u ¯ | | L 1 ≤ C | | ∇ u | | L 1. Here u ¯ is the average of u on Ω. Now I need to get the general p case, i.e., for u ∈ W 1, p ( Ω), there is | | u − u ¯ | | L p ≤ C | | ∇ u | | L p. My professor in class ...Poincaré-Sobolev-type inequalities indisputably play a prominent role not only in the theory of Sobolev spaces but also in a wide range of applications in analysis of partial differential equations, calculus of variations, mathematical modeling or harmonic analysis (e.g. [5, 20, 44]).These types of inequalities have been exhaustively studied for decades and have been generalized in many ...Download a PDF of the paper titled Poincar\'e Inequality Meets Brezis--Van Schaftingen--Yung Formula on Metric Measure Spaces, by Feng Dai and 3 other authorsThe only reference for inequalities of Poincare type on punctured domains I could find was Lieb–Seiringer–Yngvason (Ann. Math 2003) arXiv link. I suspect the Poincaré inequality on punctured domains in the way it is asked above might be false. If it is false, then I would like to understand is what sort of functions admit the second .... 1. (1) This inequality requires f f to be differConnected by Poincaré Inequality. 11 minute read. Pub We establish the Sobolev inequality and the uniform Neumann-Poincaré inequality on each minimal graph over B_1 (p) by combining Cheeger-Colding theory and the current theory from geometric measure theory, where the constants in the inequalities only depends on n, \kappa, the lower bound of the volume of B_1 (p).Function approximation and recovery via some sampled data have long been studied in a wide array of applied mathematics and statistics fields. Analytic tools, such as the Poincaré inequality, have been handy for estimating the approximation errors in different scales. The purpose of this paper is to study a generalized Poincaré inequality, where the measurement function is of subsampled type ... The strong Orlicz-Poincaré inequality coincides with the ones consid POINCARE INEQUALITIES, EMBEDDINGS, AND WILD GROUPS ASSAF NAOR AND LIOR SILBERMAN Abstract. We present geometric conditions on a metric space (Y;d Y) ensuring that almost surely, any isometric action on Y by Gromov's expander-based random group has a common xed point. These geometric conditions involve uniform convexity and the validity of non- By Theorem 1.4 [1], we show that if there exists a Ly...

Continue Reading## Popular Topics

- We prove generalizations of the Poincaré and logarit...
- Poincaré inequality in a ball (case $1\leqsla...
- weak Poincare inequality for geodesic balls. The weak Poin...
- On the Poincare inequality´ 891 (h1) There exists R >0 such that...
- If μ satisﬁes the inequality SG(C) on Rd then (1.3) can...
- Overall, the strategy of the proof is pretty simil...
- For other inequalities named after Wirtinger, see Wirting...
- Let Omega be an open, bounded, and connected subset ...